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Three processes compose a thermodynamic cycle shown in the accompanying `P-V`, diagram of an ideal gas. Process `1 rarr 2` take place at constant temperature, during this process `60 J` of heat enters the system. Process `2 rarr 3` takes place at constant volume. During this process `40 J` of heat leaves the system. Process `3 rarr 1` is adiabatic. What is the change in internal energy of the during process `3 rarr 1`? A. `- 40 J`B. `- 20 J`C. `+ 20 J`D. `+ 40 J` |
Answer» Correct Answer - D d. `1 rarr 2` : isothermal, `Delta U_(12) = 0` `2 rarr 2`: isochoric, `Delta W = 0` `implies Delta Q_(23) = Delta U_(23) implies - 40 = Delta U_(23)` For a cyclic process, `Delta U = 0` `Delta U_(12) + Delta U_(23) + Delta U_(31) = 0` `0 + (- 40) + Delta U_(31) = 0` `0 + (-40) + Delta U_(31) = 0` `Delta U_(31) = + 40 J` |
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