Three randomly chosen nonnegative integers `x , ya n dz`are found to satisfy the equation `x+y+z=10.`Then the probability that `z`is even, is:`5/(12)`(b) `1/2`(c) `6/(11)`(d) `(36)/(55)`A. `(1)/(2)`B. `(36)/(55)`C. `(6)/(11)`D. `(5)/(11)`

Three randomly chosen nonnegative integers `x , ya n dz`are found to s

1.	Three randomly chosen nonnegative integers `x , ya n dz`are found to satisfy the equation `x+y+z=10.`Then the probability that `z`is even, is:`5/(12)`(b) `1/2`(c) `6/(11)`(d) `(36)/(55)`A. `(1)/(2)`B. `(36)/(55)`C. `(6)/(11)`D. `(5)/(11)`
Answer» Correct Answer - C Sample space `rarr ^(12)C_2` Number of possible for Z is even `z=0 rArr^(11)C_1` `z=2 rArr^(9)C_1` `z=4 rArr^(7)C_1` `z=6 rArr^(5)C_1` `z=8 rArr^(3)C_1` `z=0 rArr^(1)C_1` Total =36 `therefore " Probility " =(36)/(66)=6/(11)`

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Three randomly chosen nonnegative integers `x , ya n dz`are found to satisfy the equation `x+y+z=10.`Then the probability that `z`is even, is:`5/(12)`(b) `1/2`(c) `6/(11)`(d) `(36)/(55)`A. `(1)/(2)`B. `(36)/(55)`C. `(6)/(11)`D. `(5)/(11)`

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