1.

Three resistance, each of 1Omega,are joined in parallel. Three such combinations are put in series. The resultant resistance is

Answer»

<P>`9OMEGA`
`3OMEGA`
`1Omega`
`(1)/(3)Omega`

Solution :`R_(p)=1+1+1=3Omega, (1)/(R_(S))=(1)/(3)+(1)/(3)+(1)/(3)=(3)/(3)=1 rArr R_(S)=1Omega`


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