1.

Three resistances 2 Omega , 3 Omega and 4 Omegaare connected in parallel . The ratio of currents passing throughthem when a potential differences is appliedacross its ends will be

Answer»

`4: 3: 2`
`5: 4: 3`
`6: 4: 3`
`6: 3: 2`

SOLUTION :When resistors are connected in PARALLEL `I alpha (1)/(R )`
`rArr I_(1): I_(2) : I_(3)= (1)/(2): (1)/(3): (1)/(4) rArr I_(1): I_(2): I_(3) = 6: 4: 3`


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