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Three resistors 1 Omega, 2 Omega and 4 Omega are combined in series. What Is the total resistance of the combination ? |
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Answer» Solution :EQUIVALENT resistance of series connection of given RESISTORS, `R_(s) = R_(1) + R_(2) + R_(3)` ` = 1 + 2 + 3 ` `THEREFORE R_(s) = 6 Omega` |
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