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Three Runners A, B And C Run A Race, With Runner A Finishing 12 Meters Ahead Of Runner B And 18 Meters Ahead Of Runner C, While Runner B Finishes 8 Meters Ahead Of Runner C. Each Runner Travels The Entire Distance At A Constant Speed. What Was The Length Of The Race? |
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Answer» LETS assume distance of race = x MTRS. Then when A finishes x m , B has run (x- 12)mtrs and C has run (x-18) mtrs. => at this point B is 6 m ahead of C. Now to finish race b needs to run another 12 m, => he RUNS another 12 m. when B finishes race he is 8 m ahead of C. so last 12 m B has run, C has run 10 m.as speeds are constant, => x-12/ x-18 = 12/10 => x = 48 mtrs. Lets assume distance of race = x mtrs. Then when A finishes x m , B has run (x- 12)mtrs and C has run (x-18) mtrs. => at this point B is 6 m ahead of C. Now to finish race b needs to run another 12 m, => he runs another 12 m. when B finishes race he is 8 m ahead of C. so last 12 m B has run, C has run 10 m.as speeds are constant, => x-12/ x-18 = 12/10 => x = 48 mtrs. |
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