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Three ships A, B and C are in motion. The motion of A as seen by B is with speed v towards north-east . The motion. Of B as seen by C is with speed v towards the north-west. Then as seen by A, C will be moving towardsA. northB. southC. eastD. west |
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Answer» Correct Answer - b `vecv_(A)-vecv_(B)=v((hati+hatj)/(sqrt(2))), vecv_(B)-vecv_(C)=v((-hati+hatj)/(sqrt(2)))` Adding: `implies vecv_(A)-vecv_(C)=(2v)/(sqrt(2))hatj` `implies vecv_(C)-vecv_(A)=sqrt(2) vhatj =sqrt(2) (-hatj)` So C will be moving towards south as seen by A. or `a_(p) gt 10m//s^(2)` |
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