Three Taps A, B And C Can Fill A Tank In 12, 15 And 20 Hours Respecti

1.	Three Taps A, B And C Can Fill A Tank In 12, 15 And 20 Hours Respectively. If A Is Open All The Time And B And C Are Open For One Hour Each Alternately, The Tank Will Be Full Is?
Answer» (A + B)'s 1 HOUR work = (1/12 + 1/15) = 3/20 (A + C)'s 1 hour work = (1/12 + 1/20) = 2/15 Part filled in 2 hrs = (3/20 + 2/15) = 17/60 Part filled in 6 hrs = 3 * 17/60 = 17/20 Remaining part = 1 - 17/20 = 3/20 Now, it is the turn of A and B and 3/20 part is filled by A and B in 1 hour. Total TIME taken to FILL the tank = (6 + 1) = 7 hrs. (A + B)'s 1 hour work = (1/12 + 1/15) = 3/20 (A + C)'s 1 hour work = (1/12 + 1/20) = 2/15 Part filled in 2 hrs = (3/20 + 2/15) = 17/60 Part filled in 6 hrs = 3 * 17/60 = 17/20 Remaining part = 1 - 17/20 = 3/20 Now, it is the turn of A and B and 3/20 part is filled by A and B in 1 hour. Total time taken to fill the tank = (6 + 1) = 7 hrs.

Three Taps A, B And C Can Fill A Tank In 12, 15 And 20 Hours Respectively. If A Is Open All The Time And B And C Are Open For One Hour Each Alternately, The Tank Will Be Full Is?

Answer»

(A + B)'s 1 HOUR work = (1/12 + 1/15) = 3/20

(A + C)'s 1 hour work = (1/12 + 1/20) = 2/15

Part filled in 2 hrs = (3/20 + 2/15) = 17/60

Part filled in 6 hrs = 3 * 17/60 = 17/20

Remaining part = 1 - 17/20 = 3/20

Now, it is the turn of A and B and 3/20 part is filled by A and B in 1 hour.

Total TIME taken to FILL the tank = (6 + 1) = 7 hrs.

(A + B)'s 1 hour work = (1/12 + 1/15) = 3/20

(A + C)'s 1 hour work = (1/12 + 1/20) = 2/15

Part filled in 2 hrs = (3/20 + 2/15) = 17/60

Part filled in 6 hrs = 3 * 17/60 = 17/20

Remaining part = 1 - 17/20 = 3/20

Now, it is the turn of A and B and 3/20 part is filled by A and B in 1 hour.

Total time taken to fill the tank = (6 + 1) = 7 hrs.

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