Three unbiased coins are tossed once. Find the probability of getting

1.	Three unbiased coins are tossed once. Find the probability of getting exactly one tail
Answer» We know that, Probability of occurrence of an event = \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\) Let T be tails and H be heads Total possible outcomes = TTT, TTH, THT, HTT, THH, HTH, HHT, HHH Desired outcomes are exactly one tail. So, desired outputs are THH, HTH, HHT Total no. of outcomes are 8 and desired outcomes are 3 Therefore, the probability of getting exactly one tail = \(\frac{3}{8}\) Conclusion: Probability of getting exactly one tail is \(\frac{3}{8}\)

Three unbiased coins are tossed once. Find the probability of getting exactly one tail

Answer»

We know that,

Probability of occurrence of an event

= \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\)

Let T be tails and H be heads

Total possible outcomes = TTT, TTH, THT, HTT, THH, HTH, HHT, HHH

Desired outcomes are exactly one tail. So, desired outputs are THH, HTH, HHT

Total no. of outcomes are 8 and desired outcomes are 3

Therefore, the probability of getting exactly one tail = \(\frac{3}{8}\)

Conclusion: Probability of getting exactly one tail is \(\frac{3}{8}\)

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Three unbiased coins are tossed once. Find the probability of getting exactly one tail

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