1.

Three unbiased coins are tossed, what is the probability of getting at least 2 tails ?

Answer»

1/2



Total cases are = 2*2*2 = 8, which are as follows
[TTT, HHH, TTH, THT, HTT, THH, HTH, HHT]

Favoured cases are = [TTH, THT, HTT, TTT] = 4

So required probability = 4/8 = 1/2



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