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Three Unbiased Coins Are Tossed. What Is The Probability Of Getting At Most Two Heads?

Answer»

<P>Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

LET E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

P(E) =n(E)/n(S)=7/8.

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

P(E) =n(E)/n(S)=7/8.


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