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Three vessels contain 1 by 5 litres,3 by 10 litres and 3 by 8 litres of milk these vessels areemptied into an empty can. How much milk is there in the can? |
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Answer» ••• Step - 1 ••• • Capacity of 1st vessel = 10 L Milk : Water = 2 : 1 Ratio sum = 2 + 1 = 3 Milk = (2/3) × 10 = (20/3) l Water = (1/3) × 10 = (10/3) l • Capacity of 2ND vessel = 10 l Milk : Water = 3 : 1 Ratio sum = 3 + 1 = 4 Milk = (3/4) × 10 = (15/2) l Water = (1/4) × 10 = (5/2) l • Capacity of 3rd vessel = 10 l Milk : Water = 3 : 2 RATION sum = 3 + 2 = 5 Milk = (3/5) × 10 = 6 l Water = (2/5) × 10 = 4 l ••• Step - 2 ••• Now, three vessels are emptied into a single large vessel. Total capacity = (10 + 10 + 10) = 30 l Milk = (20/3) + (15/2) + 6 = (121/6) l Water = (10/3) + (5/2) + 4 = (59/6) l Milk : Water = (121/6) : (59/6) = 121 : 59 |
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