1.

Threshold frequency for metal surface is 4xx10^(14) Hz.When radiation of 5xx10^(14)Hz is incident on this surface ,photo-electric current obtained is 1.8 mA.If frequency of incident radiation is made half and intensity is made three times,value of photo-electric current will be.....

Answer»

0.9 mA
5.4 mA
3.6 mA
zero

Solution :Here threshold frequency,
`V_(0)=4xx10^(14)HZ`
INITIALLY V=`5xx10^(14)`Hz
Now frequency of incident radaition Is MADE half,
`v.=(5xx10^(14))/(2)=2.5xx10^(14)`Hz
For photo-electric effect v.`gtV_(0)` but here v.`ltV_(0)` hence photo-electric effect will not be obtained .Hence ,CURRENT will not be obtained .


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