Through a series of thermodynamic processes, the internal energy of a sample of confined gas is increased by 560 J. if the net amount of work done on the sample by its surroundings is 320 J, how much heat was transferred between the gas and its environment?

Through a series of thermodynamic processes, the internal energy of a

1.	Through a series of thermodynamic processes, the internal energy of a sample of confined gas is increased by 560 J. if the net amount of work done on the sample by its surroundings is 320 J, how much heat was transferred between the gas and its environment?
Answer» 240 J absorbed 240J dissipated 880 J absorbed 880 J dissipated Solution :By CONVENTION, WORK done on the gas SAMPLE is designated as negative , so in the FIRST LAW of thermodynamics, `DeltaU=Q-W`, we must write `W=-320J`. Therefore, `Q=DeltaU+W=560J+(-320J)=+240J`. Positive Q denotes heat in.

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Through a series of thermodynamic processes, the internal energy of a sample of confined gas is increased by 560 J. if the net amount of work done on the sample by its surroundings is 320 J, how much heat was transferred between the gas and its environment?

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