Tickets numbered from 1 to 12 are mixed up together, and then a ticket

1.	Tickets numbered from 1 to 12 are mixed up together, and then a ticket is withdrawn at random. Find the probability that the ticket has a number which is a multiple of 2 or 3.
Answer» We know that, Probability of occurrence of an event = \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\) Total no. of outcomes are 12 Desired output is picking a number which is multiple of 2 or 3. So, desire outputs are 2, 3, 4, 6, 8, 9, 10, 12. Total no. of desired outputs are 8 Therefore, the probability of getting a number which is multiple of 2 or 3 = \(\frac{8}{12}\) = \(\frac{2}{3}\) Conclusion: Probability of picking a ticket which is multiple of 2 or 3 is \(\frac{2}{3}\)

Tickets numbered from 1 to 12 are mixed up together, and then a ticket is withdrawn at random. Find the probability that the ticket has a number which is a multiple of 2 or 3.

Answer»

We know that,

Probability of occurrence of an event

= \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\)

Total no. of outcomes are 12

Desired output is picking a number which is multiple of 2 or 3. So, desire outputs are 2, 3, 4, 6, 8, 9, 10, 12. Total no. of desired outputs are 8

Therefore, the probability of getting a number which is multiple of 2 or 3

= \(\frac{8}{12}\)

= \(\frac{2}{3}\)

Conclusion: Probability of picking a ticket which is multiple of 2 or 3 is \(\frac{2}{3}\)

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