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Tje value of p(x) =(x-1)(×+1) for p(1) is |
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Answer» -p(x) = (x - 1)(x + 1)TO FIND :-The VALUE of p(1)SOLUTION :-➳ p(x) = (x - 1)(x + 1)As we KNOW the algebraic identity :- (a + b)(a - b) = a² - b². So LET's APPLY this identity,➳ p(x) = x² - 1²➳ p(1) = (1)² - (1)²➳ p(1) = 1 - 1➳ p(1) = 0Hence value of the GIVEN polynomial p(x) at p(1) is 0.ADDITIONAL INFORMATION :-Algebric Identities : |
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