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To activate the reaction(n,alpha) with stationary B^(11) nuclei, neutrons must have the threshold kinetic energy T_(th)=4.0MeV. Find the energy of this reaction. |
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Answer» Solution :We have `4.0=(1+(m_(n))/(M_(B^(11))))|Q|` or `Q=(11)/(12)xx4MeV= -3.67MeV` |
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