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To activate the reaction`(n,alpha)` with stationary `B^(11)` nuclei, neutrons must have the threshold kinetic energy `T_(th)=4.0MeV`. Find the energy of this reaction. |
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Answer» We have `4.0=(1+(m_(n))/(M_(B^(11))))|Q|` or `Q=(11)/(12)xx4MeV= -3.67MeV` |
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