1.

To change the strength of 25 ml of 0.15 M HCl to 0.1 M the quantity of water that is to be added is

Answer»

37.5 ml
12.5 ml
25.0 ml
18.75 ml

Solution :`N_(1)V_(1)=N_(2)V_(2)`
`0.15xx25=0.1V_(1)impliesV_(2)=37.5ml`
WATER to be ADDED`=37.5-25=12.5ml`


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