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To determine the half life of a radioactive element, a student plots a graph of In |(dN(t))/(dt)| versus t. Here (dN(t))/(dt) is the rate of radioactive decay at time t. If the number of radioactive nuclei of this element decreases by a factor of p after 4.16 years. the value of p is........... |
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Answer» Solution :In `A=-lambda t+C` `rArr ln (dN(t)//dt]=-lambdat+C` `lambda=[(4-3)//(6-4)]=1/2 ("from GRAPH")` We have, `t_(1//2)=ln 2//lambda=1.396` `N=N_(0)//2^(3)=N_(0)//8` P=8 |
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