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To divide a line segment PQ in the ratio a : b (a, b are positive integers), draw a ray PX so that ∠QPX is an acute angle and then mark points on ray PX at equal distances such that minimum number of these points is |
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Answer» divide a line SEGMENT PQ in the ratio a : b (a, b are positive integers), draw a ray PX so that ∠QPX is an acute angle and then mark points on ray PX at equal distances To Find : minimum number of these points is (1) Greater ofa and b (2) a+b (3) a+b–1(4) a+b+1Solution:To divide a line segment PQ in the ratio a:b,STEP1 : Draw a line segment PQ of some lengthStep 2 : Draw a Ray PX such that ∠QPX is an acute angleStep 3: Take a+b point on PX of Equal length one by one ( CONSECUTIVELY)Step 4 : Join a+b th Point with Q as a straight lineStep 5 : Draw a line parallel to line DRAWN in step 4 such that it passes through ath point of step 3 and intersect PQ at MM divides PQ in to a : b Ratio.a+b points are required Learn More:To divide a line segment BC internally in the ratio 3 : 5, we draw a ...brainly.in/question/25266911to divide a line segment BC internally in the ratio 3:5 we draw a ray ...brainly.in/question/25659568 |
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