1.

To estimate `g` (from `g = 4 pi^(2)(L)/(T^(2))`), error in measurement of `L` is `+- 2%` and error in measurement of `Tis +- 3%` The error in estimated `g` will beA. `+- 8%`B. `+- 6%`C. `+- 3%`D. `+- 5%`

Answer» Correct Answer - a
`g = 4 pi^(2) (L)/(T^(2))`
`(Delta L)/(L) = 2% = +- 2 xx 10^(-2)`
`(Delta T)/(T) = 3% = +- 3 xx 10^(-2)`
`rArr (Delta g)/(g) = (Delta L)/(L) +(2Delta T)/(T) =2 xx 10^(-2)+ 2 xx 3 xx 10^(-2)`
`8 xx 10^(-2)= +- 8%`


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