InterviewSolution
Saved Bookmarks
| 1. |
To find the resistance of a galvanometer by the half deflection method the following circuit is used with resistances R_1 =9970 Omega , R_2 = 30 Omegaand R_3= 0. The deflection in the galvanometer is d. With R_3, =107Omegathe deflection changed to (d) /(2) the galvanometer resistance is approximately: |
|
Answer» `107Omega ` |
|