1.

To find the resistance of a galvanometer by the half deflection method the following circuit is used with resistances R_1 =9970 Omega , R_2 = 30 Omegaand R_3= 0. The deflection in the galvanometer is d. With R_3, =107Omegathe deflection changed to (d) /(2) the galvanometer resistance is approximately:

Answer»

`107Omega `
`137Omega `
`107 // 2OMEGA `
`77Omega `

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