1.

To get 2F capacitance, the area of each plate kept at separation of 2 mm is ...... . ' (epsilon_(0) = 8.85 xx 10^(-12) MKS)

Answer»

`4xx10^(5) m^(2)`
`4.51 xx10^(5) m^(2)`
`4.51xx10^(8)cm^(2)`
`4.51 xx10^(8) m^(2)`

Solution :`C = (epsilon_(0)A)/(d)`
`:. A = (Cd)/(epsilon_(0))= (2xx2xx10^(-3))/(8.85xx10^(-12))`
`:. A = 0.4519xx10^(9)`
`:. A = 4.519xx10^(8) m^(2)`


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