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To get a rsultant displacement of 10m, two displacement vectors, one of magnetic 6 m and another of 8 m,should be combined :A. parallelB. anti-parallelC. at an angle `60^(@)`D. perpendicular to each |
Answer» Correct Answer - D Let `|vecr_(1)|= 6m " "|vecr_(2)|= 8m and |vecr|=10m` Then `sqrt(r_()^(2) + r_(2)^(2) + 2r_(1)r_(2) cos theta) = 10` `6^(2) + 8^(2) + 2r_(1)r_(2) cos theta = 10^(2)` `" "cos theta = 0^(@)` `" "theta= (pi)/(2)` |
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