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To mainntain a rotor at a uniform angular speed of `200 s^(-1)`, an engine needs to transmit a torque of `180 N-m`. What is the power of the engine required ? |
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Answer» Here, `omega = 200 s^(-1), tau 180N-m,P = ?` As `P = tau omega :. P = 180 xx 200 = 36000 "watt" = 36 kW` |
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