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To neutralise completely 20 ml of 0.1 M aqueous solution of phosphorousacid (H_3PO_3), the volume of 0.1 M aqueous KOH solution required is : |
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Answer» Solution :`H_3PO_3 ` is dibasic acid `H_3PO_3 + 2KOH to K_2HPO_3 + 2H_2O` `(M_1V_1)/(n_1)=(M_2V_2)/(n_2)` `(0.1 xx 20)/(1) = (0.1 xx V_2)/(2)` `V_2=(0.1 xx 20 x 2)/(0.1) = 40` ml |
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