To obtain the X-rays of shortest wavelength of0.5Å, potential difference applied across the electrodes of the tube should be:

To obtain the X-rays of shortest wavelength of0.5Å, potential differe

1.	To obtain the X-rays of shortest wavelength of0.5Å, potential difference applied across the electrodes of the tube should be:
Answer» 13.89 kV 19.72kV 21.7kV 24.8kV Solution :`E=hv=EV` `:.(hc)/(LAMBDA)=eV rArr V=(hc)/(e lambda)=24*8kV`

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To obtain the X-rays of shortest wavelength of0.5Å, potential difference applied across the electrodes of the tube should be:

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