1.

To prepare solution of certain substance, 300 gm is used for 25% solution and 400 gm for 40% solution, then what is the mass percentage of solute present in this solution mixture ?

Answer»

`33.57`
`66.43`
`87.23`
`19.24`

Solution :In solution - 1, mass of solute `= (25)/(100)xx300=75` gm
In solution - 2, mass of solute `=(40)/(100)xx400=160` gm
So, total mass of solute on MIXING two solution is= 235 gm
So, total mass of solution = 700 gm
So, % solute PRESENT in final solution
`= (235)/(700)xx100=33.57%`


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