1.

To produce 160 g of oxygen , the number of mole of water required to be electrolysed is

Answer»

2.5
5
10
20

Solution :`H_(2) O to H_(2) + (1)/(2) O_(2)`.
Mole ratio of `H_(2)O : O_(2) :: 1 : (1)/(2)IMPLIES 1 : 0.5`
`therefore` For 1 mole of `H_(2)O -= 0.5 ` moles = 16 G of `O_(2)` .
n moles of `H_(2)O -= 160` g of `O_(2)` .
No. of moles of WATER REQUIRED `therefore n = (160)/(16) = 10`


Discussion

No Comment Found

Related InterviewSolutions