1.

To reduce de-Broglie wavelength of an electron from 10^(-10) m to0.5xx10^(-10) m,its energy should be …

Answer»

increased to 4 times
doubled
halved
decreased to fourth part

Solution :`LAMBDA=(h)/(sqrt(2mK))`
`therefore K prop (1)/(lambda^(2))`
`therefore (K_(2))/(K_(1))=((lambda_(1))/(lambda_(2)))^(2)=((10^(-10))/(0.5xx10^(-10)))^(2)=4`
`therefore K_(2)=4K_(1)`


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