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To send 10% of the main current through a moving coil galvanometer of resistance `99omega`, the shunt required is –A. `9.9 Omega`B. `10 Omega`C. `11 Omega`D. `9 Omega` |
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Answer» Correct Answer - C Required resistance which should be added in series so that , the current in the circuit is given by Initial resistance = Final resistane i.e., `G=((Gs)/(G+s))+R` `therefore R=G-((GS)/(G+S))=(G^2)/(G+S)`. |
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