Today is my birthday please help me only math Aryabhatta please answer

1.	Today is my birthday please help me only math Aryabhatta please answer this question
Answer» $\: \: \: \huge{\underline{\underline{\textsf{\maltese{\red{answer}}}}}}$ Q.1) a + ( b + c ) = ( a + b ) + c ➭ Substitute the VALUES, -» -25+ [20+ (-10) = [(-25) +20] + (-10) Solve the RHS with BRACKETS first, Solve the LHS with brackets first, -» -25 + 10 = [(-25) +20] + (-10) Add the integers in LHS, -» -15= [(-25) +20] + (-10) -» -15=(-5)+ (-10) Add the integers in RHS, -» -15= -15 Comparing both SIDES, LHS = RHS Thus, verified. ------------------------------------- 2) a × (b + c) = a × b + a × c Solution: Substitute the values, -» -25 x [20+ (-10)] = (-25) × 20 + (-25) × (-10) Solve the LHS with brackets first, -» -25 x 10 = (-25) 20+ (-25) (-10) MULTIPLY the integers, -» 250 = (-25) x 20 + (-25) × (-10) Solve the RHS using BODMAS rule, -» -250 = -500 + 250 Add the integers, -» -250 = -250 Comparing both sides, LHS = RHS Thus, verified. hope it was helpful to you

Today is my birthday please help me only math Aryabhatta please answer this question

Answer»

$\: \: \: \huge{\underline{\underline{\textsf{\maltese{\red{answer}}}}}}$

Q.1) a + ( b + c ) = ( a + b ) + c

➭ Substitute the VALUES,

-» -25+ [20+ (-10) = [(-25) +20] + (-10)

Solve the RHS with BRACKETS first,

Solve the LHS with brackets first,

-» -25 + 10 = [(-25) +20] + (-10)

Add the integers in LHS,

-» -15= [(-25) +20] + (-10)

-» -15=(-5)+ (-10) Add the integers in RHS,

-» -15= -15

Comparing both SIDES,

LHS = RHS

Thus, verified.

-------------------------------------

2) a × (b + c) = a × b + a × c

Solution: Substitute the values,

-» -25 x [20+ (-10)] = (-25) × 20 + (-25) × (-10)

Solve the LHS with brackets first,

-» -25 x 10 = (-25) 20+ (-25) (-10)

MULTIPLY the integers,

-» 250 = (-25) x 20 + (-25) × (-10)

Solve the RHS using BODMAS rule,

-» -250 = -500 + 250

Add the integers,

-» -250 = -250

Comparing both sides,

LHS = RHS

Thus, verified.