toog ofteam at loge.

1.	toog ofteam at loge.
Answer» Let the final temperature be T on equating the heat exchanged value Given thatlatent heat of fusion = 80 cal/glatent heat of vaporisation = 540 cal/gsp. heat capacity of water =1 cal/g/°csp. heat capacity of ice =0.5 cal/g/°c so, 80080 + 800(1/2)(T-0) = 100540 + 100(1)(100-T) => 64000 + 400T = 54000 + 10000 -100T => 500T = 0 and , T = 0° the composition is water at 0° C

Answer»

Let the final temperature be T on equating the heat exchanged value

Given thatlatent heat of fusion = 80 cal/glatent heat of vaporisation = 540 cal/gsp. heat capacity of water =1 cal/g/°csp. heat capacity of ice =0.5 cal/g/°c

so, 800*80 + 800*(1/2)*(T-0) = 100*540 + 100*(1)*(100-T)

=> 64000 + 400T = 54000 + 10000 -100T => 500T = 0

and , T = 0°

the composition is water at 0° C

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toog ofteam at loge.

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