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toog ofteam at loge.

Answer» <p>Let the final temperature be T on equating the heat exchanged value </p><p> Given thatlatent heat of fusion = 80 cal/glatent heat of vaporisation = 540 cal/gsp. heat capacity of water =1 cal/g/°csp. heat capacity of ice =0.5 cal/g/°c</p><p>so, 800*80 + 800*(1/2)*(T-0) = 100*540 + 100*(1)*(100-T) </p><p>=&gt; 64000 + 400T = 54000 + 10000 -100T =&gt; 500T = 0</p><p>and , T = 0° </p><p>the composition is water at 0° C </p>


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