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Took At a social sports club with 290 members in it. It was found that 120 played tennis110 played tennikoit, 130 played Badminton, 70 played both tennis and tennikoit, 55played tennikoit and Badminton, 60 played tennis and Badminton. It was alsodiscovered that 75 members had joined only for the social side of the club and did notplay any of the three games. How many played all the three games. |
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Answer» no.of MEMBERS play all the three games is 15Step-by-step explanation:total members= 290mebers play tennis n(t)=120members play tennikoit n(tk)=110members play badminton n(b)=130members play tennis and tennikoit n(t ^ tk)= 70members play tennikoit and badminton n(tk^b)=55members play badminton and tennis n(t ^ b)=60members play nothing is 75members play all the three games n(t^tk^b) n(tUtkUb)= n(t)+n(tk)+n(b)-n(t^tk)-n(tk^b)-n(t^b)+n(t^tk^b) therefore n(t^tk^b)= n(tUtkUb)-(n(t)+n(tk)+n(b)-n(t^tk)-n(tk^b)-n(t^b))n(t^tk^b)= 290-(120+110+130-70-55-60)n(t^tk^b)= 290-275= 15 PLEASE give me a heart ❤️ and follow if the ANSWER is useful to you |
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