1.

Total energy of electron in an excited state of hydrogen atom is -3.4eV . The kinetic and potential energy of electron on this state

Answer»

`K=-3.4eV U=-6.8eV`
`K=3.4eV U=-6.8eV`
`K=-6.8eV U=+3.4eV`
`K=+10.2eV U=-13.6eV`

SOLUTION :`K=(Ze)/(8piepsilon_(0)R)(eV)`
`U=(-ze)/(4piepsilon_(0)r)(eV)=2E_(K)`
`E_(K)=(-ze)/(8piepsilon_(0)r)`


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