1.

Total heat required to convert 50 kg of water at 10^(@)C to steam at 100^(@)C (L.H =2.25 xx 10^(6)" J kg"^(-1)):

Answer»

`3.13xx10^(6) cal`
`31.3 xx10^(6) cal`
`313 k cal`
`31.3 k cal`

SOLUTION :Here `Q=Cm DELTA Q +ML`
`1000 xx50 xx(100-10)+(50xx2.25xx10^(6))/(4.2)`
`=4.5xx10^(6)+26.8xx10^(6)=31.3xx10^(6)` cals.
`therefore` Correct CHOICE is (b).


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