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InterviewSolution
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Total number of electrons present in 1.7g of ammonia is6.022 x 10上76.022 x 101.76:022 x 11.76022 X 103 bd) |
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Answer» 1.7 g of the ammonia contains (6.022× 10²³) ×1.7/17atoms. Now, 1 atom of the Ammonia contains 7 + 3 electrons = 10 electrons. ∴6.022× 10²² atoms of the Ammonia contains 10 ×6.022× 10²² electrons. Hence, the number of the electrons in 1.7 g of the Ammonia is6.022× 10²³ electrons. |
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