1.

Tow short electric dipoles are placed as shown The energy or electric interaction between these dipoles will be.

Answer»

` (2 K P_1p_2 COS theta)/r^2 `
` (-2 kP1p_2 cos theta)/r^3`
`(-2 P_1p2 sin theta)/r^3`
` (-4 kP_1P_2 cos theta)/r^3`

Solution : Potenial energy of ` P_2` in the FIELD of ` P_1`
` =- P_2 E_1 cos theta `
` =- P_2 (2 KP_1 COSQ)/r^3`
` U=- (2 KP_1OP_2)/r^3 cos theta`
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