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Triangle pqr and triangle abc, ar triangle pqr=27cm² ar triangle abc =75cm², bc= 10cm find qr |
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Answer» ∵ΔABC∼ΔPQR∴ AR(ΔPQR)ar(ΔABC) = QR 2 BC 2 ⇒ 4936 = QR 2 12 2 ⇒(QR) 2 = 3612×12×49 =4×49⇒QR=+ 4×49 =2×7=14cm |
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