1.

Tube A has both ends open, while B has on end closed otherwise the two tubes are identical. What Is the ratio of fundamental frequency of the tubes A and B?

Answer»

The fundamental frequency for tube A with both ends open is fA = \(\frac{v}{2L}\)

The fundamental frequency for tube B with one end closed is \(f_B = \frac{v}{4L}\)

\(\frac{f_A}{f_B}\) = \(\frac{v/lL}{v/4L}\) = 2

⇒ fA : fB = 2 : 1



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