1.

Tw3o pendulum difer in lengths by 22 cm. They oscillate att the same placeos that one of them makes30 oscillationsand the othermakes 36 oscillationsduring the same time. The lengths (in cm) of thependulums are

Answer»

72 and 50
60 and 38
50 and 28
80 and 58

Solution :Time of pendulum is
`T = 2pi sqrt(L/g) therefore T_(1)/T_(2) = sqrt(l_(1)/l_(2))`
Also , ` T_(1)/T_(2) = N_(2)/N_(1) " Where N_(1) = 30 and N_(2) = 36 `
` Sqrt(l_(1)/l_(2)) = N_(2)/N_(1) = 36/30`
GIVEN ` l_(1) - l_(2) = 22 cm `
Solvingthe eqns , (i) and (II) we got
` l_(1) = 72 cm and l_(2) = 50 cm `


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