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Tw3o pendulum difer in lengths by 22 cm. They oscillate att the same placeos that one of them makes30 oscillationsand the othermakes 36 oscillationsduring the same time. The lengths (in cm) of thependulums are |
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Answer» 72 and 50 `T = 2pi sqrt(L/g) therefore T_(1)/T_(2) = sqrt(l_(1)/l_(2))` Also , ` T_(1)/T_(2) = N_(2)/N_(1) " Where N_(1) = 30 and N_(2) = 36 ` ` Sqrt(l_(1)/l_(2)) = N_(2)/N_(1) = 36/30` GIVEN ` l_(1) - l_(2) = 22 cm ` Solvingthe eqns , (i) and (II) we got ` l_(1) = 72 cm and l_(2) = 50 cm ` |
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