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twevle cells , each having emf E volt are connected in series ans are kept in a closed box. Some of these cells are wrongly connected with positive and negative terminals reversed . This 12 cell battery is connected In series with an ammeter , an external resistance R ohms adn a two -cell battery (two cells of the same type used earlier , connectedperfectly in sesries) . The current in the circuit when the 12 cell battery oppose each other Then , the number of cellsij 12 - cells battery that are connected wrongly is |
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Answer» Solution :`R=(PL)/(A)` `L= (RA)/(P) = (4xxpixx(1.4xx10^(-3))^2)/(2.2xx10^(-8)xx4` = 280m |
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