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Two aeroplanes I and II bomb a target in succession. The probabilities of I andII scoring a hit correctly are 0.3 and 0.2, respectively. The second planewill bomb only if the first misses the target. The probability that thetarget is hit by the second plane is(A) `0.06` (B) `0.14`(C) `7/22` (D) `0.7` |
Answer» `P=0.7xx0.2+(0.7xx0.8)(0.7xx0.2)+(0.7xx0.8)^2(0.7xx0.2)+..........` `=0.14[1+0.56+0.56^2+...........]` `=0.14[(1)/(1-056)]` `=0.14/(0.14)` `=7/22` |
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