InterviewSolution
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InterviewSolution
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Two alternating voltage generators produce emfs of the same amplitude`(E_0)` but with a phase difference of `(pi)//3`. The resultant emf isA. (A) `E_0 sin [ omega t+(pi)//3)]`B. (B) `E_0 sin [ omega t+(pi)//6)]`C. (C) `sqrt(3)E_0 sin [omega t+(pi)//6)]`D. (D) `sqrt(3)E_0 sin [ omega t+(pi)//2)]` |
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Answer» Correct Answer - C `E_(1)=(E_0) sin omega t, (E_2)=(E_0) sin [ omega t + (pi//3)]` `E=(E_2)+(E_1)` `=(E_0)sin (omega t +(pi//3)]+(E_0)sin omegat` `(E_0) [ 2 sin {omega t+(pi//6)}cos (pi//6)]` `= sqrt(3) (E_0) sin [omega t +(pi//6)]`. |
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