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Two alternating voltage generators produce emfs of the same amplitude`(E_0)` but with a phase difference of `(pi)//3`. The resultant emf isA. `E_(0)sin(omegat+pi//3)`B. `E_(0)sin(omegat+pi//6)`C. `sqrt(3)E_(0)sin(omegat+pi//6)`D. `sqrt(3)E_(0)sin(omegat+pi//2)` |
Answer» Correct Answer - C `E_(1)=E_(0)sin omegat , E_(2)=E_(0)sin (omegat+pi//3)`, `E=E_(2)+E_(1)` `=E_(0)sin (omegat+pi//3)+E_(0)sin omegat` `=E_(0)(2sin(omegat+pi//6)cos(pi//6)` `=sqrt(3) sin sin (omegat+pi//6)` |
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