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Two angles of a quadrilateral measure 85° and 75° respectively. The other two angles are equal. Find the measure of each of these equal angles. |
Answer» Let x be the common angle of quadrilateral. As per question, \(\angle\)A = 85° \(\angle\)B = 75° \(\angle\)C = \(\angle\)D = x As we know that, Sum of all four angles of quadrilateral is 360o \(\angle\)A + \(\angle\)B + \(\angle\)C + \(\angle\)D = 360° 85° + 75°+ x + x = 360° 2x = 360° - (85° + 75°) 2x = 200° X = 200 / 2 = 100° \(\angle\)C = \(\angle\)D = 100° So, Two angles of quadrilateral whose measuring’s are equal is 100°. |
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