InterviewSolution
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InterviewSolution
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Two astronauts have deserted their spaceship in a region of space far from the gravitational attraction of any other body. Each has a mass of `100 kg` and they are `100 m` apart. They are initially at rest relative to one another. How long will it be before the gravitational attraction brings them `1 cm` closer together?A. 2.52 daysB. 1.41 daysC. 0.70 dayD. 0.41 day |
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Answer» Correct Answer - B Here `m_(1)=m_(2)=100 kg , r=100 m` Accelerations of first and second astronauts are `a_(1)=(Gm_(1)m_(2))/(r^(2))xx(1)/(m_(1))=(Gm_(2))/(r^(2))` and `a_(2)=(Gm_(1)m(2))/(r^(2))xx(1)/(m^(2))=(Gm_(1))/(r^(2))` Net acceleration of approach `a=a_(1)+a_(2)=(GM_(2))/(r^(2))+(Gm_(1))/(r^(2))=(2Gm_(1))/(r^(2))` `=(2xx(6.67xx10^(-11))xx100)/(100)^(2)=2xx6.67xx10^(-13) ms^(-2)` on solving we get t = 1.41 days |
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