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InterviewSolution
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Two astronauts have deserted their spaceship in a region of space far from the gravitational attraction of any other body. Each has a mass of `100 kg` and they are `100 m` apart. They are initially at rest relative to one another. How long will it be before the gravitational attraction brings them `1 cm` closer together?A. `2.52`daysB. `1.41` daysC. `0.70` daysD. `1.41 s` |
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Answer» Correct Answer - B `a_(1)` acceleration of first `=(Gm_(1)m_(2))/(r_(2))xx1/m-1=(Gm_2)/(r^(2))=(6.67xx10^-11xx100)/((100)^(2))` `=6.67xx10^(-13)ms^(-1)` `a_(2)=` acceleration of second `=(Gm_(1))/(r^(2))=(6.67xx10^(-11)xx100)/((100)^(2))=6.67xx10^(-13)ms^(-1)` Net acceleration of approach `a=a_(1)+a_(2)=2xx6.67xx10^(-13)ms^(-1)` Now `s=1/2at^(2)` `1xx10^(-2)=1/2xx6.67xx10^(-13)xx2xxt^(2)` Solving we get `t=1.41`days. |
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