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Two bar magnet oscillating of periodic time is 2:1. If interial of mass is constant then the ratio of magnetic dipole moment .......

Answer»

`1:2`
`1:4`
`2:1`
`4:1`

Solution :`T = 2PI sqrt((I)/( mB))`
`(T_2)/( T_1) = sqrt((m_(1) B)/( m_(2) B)`
`(T_2)/( T_1) = sqrt((m_1)/( m_2))`
`THEREFORE (1)/(2)= sqrt((m_1)/( m_2) ) ""[because (T_1)/( T_2) = (2)/(1) ]`
`therefore (1)/(4) = (m_1)/(m_2)`
`therefore (m_1)/(m_2) = 1:4`


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